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well, you can make a stab at it & get some sort of an estimate
in return, people will have to do some homework & find all the major banked & unbanked tracks in the world
now, rather than waffling on about angle of bank, let's just assume the maximum height of lane 6 above the flat ( if you do find the angle of the bank, relative to the inner lane ( NOT along the lane ), the height is just:
sine angle * (1.22 * 5)
( each lane is 1.22m( it is outdoors !) & assuming that lane 1 ( 20cm from edge is race distance measure ) is 0m elevation ))
interestingly, on the Big Guy'z site, he said the angle is upto 18 degrees, which gives ~ 1.9m)
anyhows, we'll just assume it ranges from 1 - 2m
i tried just a simple energy consideration method to get an estimate ( don't know how good it is, but it's a start )
well, when a guy runs on a bank ( assuming starting at it's peak, halfway round it, which i suggested is the case in another post ), he starts at the highest point & during the course of the race, he will drop from that ht. to zero level, acquiring PE which will increase his KE compared to the flat
now PE = mgh
& KE = 0.5mv^2
(we can ignore mass from now one as it will cancel out )
the equation you get is
0.5V^2 = (gh) + (0.5v^2)
where V is actual speed in banked race, assuming lane 6 & v is theoretical speed on unbanked track
i won't bore you with the workings, but it boils down to,
for a 200m race:
t = (40,000 T) / ( 40,000 - (2ghT))
where t is theoretical time on unbanked track in lane 6 & T is actual time run on the banked track
in return, people will have to do some homework & find all the major banked & unbanked tracks in the world
now, rather than waffling on about angle of bank, let's just assume the maximum height of lane 6 above the flat ( if you do find the angle of the bank, relative to the inner lane ( NOT along the lane ), the height is just:
sine angle * (1.22 * 5)
( each lane is 1.22m( it is outdoors !) & assuming that lane 1 ( 20cm from edge is race distance measure ) is 0m elevation ))
interestingly, on the Big Guy'z site, he said the angle is upto 18 degrees, which gives ~ 1.9m)
anyhows, we'll just assume it ranges from 1 - 2m
i tried just a simple energy consideration method to get an estimate ( don't know how good it is, but it's a start )
well, when a guy runs on a bank ( assuming starting at it's peak, halfway round it, which i suggested is the case in another post ), he starts at the highest point & during the course of the race, he will drop from that ht. to zero level, acquiring PE which will increase his KE compared to the flat
now PE = mgh
& KE = 0.5mv^2
(we can ignore mass from now one as it will cancel out )
the equation you get is
0.5V^2 = (gh) + (0.5v^2)
where V is actual speed in banked race, assuming lane 6 & v is theoretical speed on unbanked track
i won't bore you with the workings, but it boils down to,
for a 200m race:
t = (40,000 T) / ( 40,000 - (2ghT))
where t is theoretical time on unbanked track in lane 6 & T is actual time run on the banked track
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